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The problem at hand involves determining the expected number of loops formed when randomly tying ends of ropes together. Let's break down the solution step-by-step:
Initial Selection:
Subsequent Selections:
The expected number of loops E(N) can be defined recursively:
Base Case: If there is only 1 rope (N = 1), the expected number of loops is 1 because the only two ends will be tied together.
Recursive Case: For N > 1, the expected number of loops is given by:
E(N)=2N−11+E(N−1)
This formula accounts for the probability of forming a loop in the current selection and the expected loops from the remaining ropes.
The recursive formula can be expanded into a summation:
E(N)=∑k=1N2k−11
This represents the expected number of loops as the sum of probabilities of forming loops at each step, from 1 to N.
The expected number of loops formed when randomly tying ends of ropes is calculated by summing the probabilities of forming loops at each step, represented by the formula:
E(N)=∑k=1N2k−11
This approach effectively models the stochastic process of tying ends and offers a clear method to calculate expected loops for any given number of ropes N.