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Data Interview Question

Gender-Based Order Value Differences

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Solution & Explanation

To determine whether the difference in average order value (AOV) between men and women is statistically significant, we need to perform a hypothesis test. Given the data:

  • Men:
    • Average Order Value (AOV) = $46.3
    • Total Purchases (n1) = 2500
  • Women:
    • Average Order Value (AOV) = $50.2
    • Total Purchases (n2) = 3500

We will use a two-sample t-test, which is suitable for comparing the means of two independent groups when the population variances are unknown and sample sizes are large.

Steps to Perform the Hypothesis Test:

  1. State the Hypotheses:

    • Null Hypothesis (H0): There is no significant difference in AOV between men and women. μ1μ2=0\mu_1 - \mu_2 = 0
    • Alternative Hypothesis (H1): There is a significant difference in AOV between men and women. μ1μ20\mu_1 - \mu_2 \neq 0
  2. Choose the Significance Level (α\alpha):

    • Typically, α\alpha is set to 0.05.
  3. Calculate the Test Statistic:

    • The test statistic for a two-sample t-test is given by: t=(xˉ1xˉ2)s12n1+s22n2t = \frac{(\bar{x}_1 - \bar{x}_2)}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}}
    • xˉ1\bar{x}_1 and xˉ2\bar{x}_2 are the sample means.
    • s12s_1^2 and s22s_2^2 are the sample variances, which are not provided but can be estimated if needed.
    • n1n_1 and n2n_2 are the sample sizes.
  4. Determine the Degrees of Freedom (df):

    • For unequal sample sizes and variances, use the Welch-Satterthwaite equation: df=(s12n1+s22n2)2(s12n1)2n11+(s22n2)2n21df = \frac{\left(\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}\right)^2}{\frac{\left(\frac{s_1^2}{n_1}\right)^2}{n_1-1} + \frac{\left(\frac{s_2^2}{n_2}\right)^2}{n_2-1}}
  5. Find the Critical Value(s):

    • Use a t-distribution table or calculator to find the critical value(s) for the chosen α\alpha and calculated df.
  6. Decision Rule:

    • If the absolute value of the test statistic is greater than the critical value, reject the null hypothesis.
    • Otherwise, fail to reject the null hypothesis.

Conclusion:

Based on the calculation provided in the comments:

  • Calculated t-value = -1.77
  • Degrees of freedom (df) = 2998
  • Critical value for α=0.05\alpha = 0.05 and df = 2998 is approximately ±1.96

Since the absolute value of the calculated t-statistic (-1.77) is less than the critical value (1.96), we fail to reject the null hypothesis. Therefore, there is no statistically significant difference in the average order value between men and women at a 5% significance level.