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Data Interview Question

Minimum Sample Size for Confidence

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Solution & Explanation

To determine the minimum sample size NN required to ensure that the sample's conversion rate P^\hat{P} is within δ\delta of the actual click-through rate PP, with a confidence level of 95%, we need to leverage the properties of the sampling distribution of the sample proportion.

Key Concepts:

  1. Confidence Interval:

    • A confidence interval gives an estimated range of values which is likely to include an unknown population parameter, the estimated range being calculated from a given set of sample data.
    • For a 95% confidence interval, the critical value ZZ is 1.96.
  2. Margin of Error (δ\delta):

    • The margin of error defines how much the sample estimate P^\hat{P} can deviate from the true population parameter PP.
    • It is calculated using the formula: δ=Z×P^(1P^)N\delta = Z \times \sqrt{\frac{\hat{P}(1 - \hat{P})}{N}}
  3. Solving for Sample Size (NN):

    • Rearrange the margin of error formula to solve for NN: δ=1.96×P^(1P^)N\delta = 1.96 \times \sqrt{\frac{\hat{P}(1 - \hat{P})}{N}} (δ1.96)2=P^(1P^)N\left(\frac{\delta}{1.96}\right)^2 = \frac{\hat{P}(1 - \hat{P})}{N} NP^(1P^)(δ1.96)2N \geq \frac{\hat{P}(1 - \hat{P})}{\left(\frac{\delta}{1.96}\right)^2}

Explanation:

  • Binomial Distribution:

    • Since we are dealing with a click-through rate, our data follows a binomial distribution where each click is a success (click) or failure (no click).
  • Normal Approximation:

    • For large NN, the sampling distribution of P^\hat{P} can be approximated by a normal distribution due to the Central Limit Theorem.
  • Confidence Level:

    • 95% confidence level corresponds to a ZZ value of 1.96. This means that we expect 95% of the sample proportions to fall within δ\delta of the true population proportion.
  • Plug in Values:

    • To determine NN, you need an estimate of P^\hat{P}. If P^\hat{P} is not known, a conservative approach is to use P^=0.5\hat{P} = 0.5 because it maximizes the product P^(1P^)\hat{P}(1 - \hat{P}), leading to a larger sample size.
  • Final Formula:

    • The formula to find the minimum NN is: N1.962×P^(1P^)δ2N \geq \frac{1.96^2 \times \hat{P}(1 - \hat{P})}{\delta^2}
    • Use this formula to calculate NN for different values of P^\hat{P} and δ\delta based on your specific requirements.

This formula ensures that your sample size is sufficient to estimate the click-through rate with the desired precision and confidence.