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Data Interview Question

Friends Sitting Together

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Solution & Explanation

To solve the problem of finding the probability that all 10 friends sit consecutively in a row of 20 seats, we need to consider both the total number of possible seating arrangements and the number of favorable arrangements where the friends sit together.

Step-by-Step Breakdown:

  1. Total Possible Arrangements:

    • We begin by calculating the total number of ways to choose 10 seats out of 20 for the friends.

    • This is given by the combination formula (2010)\binom{20}{10}, which calculates the number of ways to choose kk items from nn items without regard to order:

      (2010)=20!10!10!\binom{20}{10} = \frac{20!}{10! \cdot 10!}

    • Using a calculator, this evaluates to 184,756184,756 ways.

  2. Favorable Arrangements (Friends Sitting Together):

    • To ensure all 10 friends sit next to each other, consider them as a single block or unit.
    • This block can be placed in different positions along the row.
    • There are 11 possible starting positions for this block of 10 seats:
      • Seats 1 to 10
      • Seats 2 to 11
      • Seats 3 to 12
      • ...
      • Seats 11 to 20
    • Thus, there are 11 ways to arrange the block of friends consecutively.
  3. Calculate the Probability:

    • The probability is the ratio of the number of favorable arrangements to the total number of possible arrangements:

      Probability=Number of favorable arrangementsTotal number of possible arrangements\text{Probability} = \frac{\text{Number of favorable arrangements}}{\text{Total number of possible arrangements}}

    • Substituting the values:

      Probability=11184,756\text{Probability} = \frac{11}{184,756}

    • This simplifies to approximately 0.00005960.0000596, or about 0.00596%.

Explanation of Steps:

  • Why 11 Positions?

    • The friends, treated as a single block, can start at position 1 and go up to position 11, ensuring they occupy 10 consecutive seats each time.
  • Why Use Combinations?

    • We use combinations because the order of choosing which seats the friends occupy doesn't matter — only which seats are occupied.
  • Simplification:

    • The 10!10! terms cancel out when considering the arrangement of friends within the block because we're only interested in their collective positioning.

Conclusion:

The probability of all 10 friends sitting consecutively in a row of 20 seats is extremely low, at approximately 0.00596%. This highlights the rarity of such an arrangement occurring purely by chance.