Data Interview Question

Receiving Spam Emails

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Solution & Explanation

To solve this problem, we need to determine the probability that at least 5 out of 100 received emails are spam. This is a classic binomial probability problem, where we have:

  • Number of trials (n): 100 (the number of emails)
  • Probability of success (p): 0.10 (probability of an email being spam)
  • Number of successes (k): at least 5

Approach

  1. Understand the Problem: We want to find the probability that at least 5 emails are spam. This can be expressed as P(X5)P(X \geq 5).

  2. Use the Complement Rule: Instead of directly calculating P(X5)P(X \geq 5), it's simpler to calculate P(X<5)P(X < 5) and then use the complement rule:

    P(X5)=1P(X<5)=1P(X4)P(X \geq 5) = 1 - P(X < 5) = 1 - P(X \leq 4)

  3. Calculate P(X4)P(X \leq 4): This involves summing up the probabilities of receiving 0, 1, 2, 3, or 4 spam emails:

    P(X4)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

  4. Use the Binomial Probability Formula:

    The binomial probability formula is:

    P(X=k)=(nk)pk(1p)nkP(X = k) = \binom{n}{k} \cdot p^k \cdot (1-p)^{n-k}

    Where:

    • (nk)\binom{n}{k} is the number of combinations of nn items taken kk at a time, calculated as n!k!(nk)!\frac{n!}{k!(n-k)!}.
  5. Calculate Each Probability:

    • P(X=0)P(X = 0):

      P(X=0)=(1000)(0.1)0(0.9)1000.00003P(X = 0) = \binom{100}{0} \cdot (0.1)^0 \cdot (0.9)^{100} \approx 0.00003

    • P(X=1)P(X = 1):

      P(X=1)=(1001)(0.1)1(0.9)990.0003P(X = 1) = \binom{100}{1} \cdot (0.1)^1 \cdot (0.9)^{99} \approx 0.0003

    • P(X=2)P(X = 2):

      P(X=2)=(1002)(0.1)2(0.9)980.0017P(X = 2) = \binom{100}{2} \cdot (0.1)^2 \cdot (0.9)^{98} \approx 0.0017

    • P(X=3)P(X = 3):

      P(X=3)=(1003)(0.1)3(0.9)970.006P(X = 3) = \binom{100}{3} \cdot (0.1)^3 \cdot (0.9)^{97} \approx 0.006

    • P(X=4)P(X = 4):

      P(X=4)=(1004)(0.1)4(0.9)960.015P(X = 4) = \binom{100}{4} \cdot (0.1)^4 \cdot (0.9)^{96} \approx 0.015

  6. Sum These Probabilities:

    P(X4)=0.00003+0.0003+0.0017+0.006+0.0150.023P(X \leq 4) = 0.00003 + 0.0003 + 0.0017 + 0.006 + 0.015 \approx 0.023

  7. Calculate the Complement:

    P(X5)=1P(X4)=10.0230.977P(X \geq 5) = 1 - P(X \leq 4) = 1 - 0.023 \approx 0.977

Conclusion

The probability that at least 5 out of 100 received emails are spam is approximately 0.977 or 97.7%. This high probability suggests that receiving a significant number of spam emails is quite likely, given the parameters of the problem.