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To craft a SQL query that generates a frequency distribution of a specific attribute with joins and sorting while handling NULL values, follow these steps:
COUNT()
to determine the frequency of the attribute.GROUP BY
to group the results by the attribute.COALESCE()
to replace NULLs with a default value if necessary.ORDER BY
to sort the results based on the frequency or the attribute itself.SELECT
COALESCE(t1.attribute, 'Unknown') AS attribute,
COUNT(*) AS frequency
FROM
table1 t1
LEFT JOIN
table2 t2 ON t1.key = t2.key
LEFT JOIN
table3 t3 ON t1.key = t3.key
WHERE
t1.attribute IS NOT NULL
GROUP BY
t1.attribute
ORDER BY
frequency DESC;
COALESCE(t1.attribute, 'Unknown')
: Replaces NULL values in attribute
with 'Unknown'.COUNT(*)
: Counts all rows, including those with NULLs in non-grouped columns.table1
, table2
, and table3
using LEFT JOINs to ensure all entries from table1
are included.attribute
is NULL, if desired.attribute
.frequency
in descending order to show the most frequent attributes first.COALESCE(attribute, 'Default')
can be used to replace NULL values with a specified default value.COUNT(attribute)
ignores NULLs, while COUNT(*)
includes all rows.This approach ensures that the SQL query effectively joins tables, groups data, and handles NULL values while providing a sorted frequency distribution of the specified attribute.