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Data Interview Question

Triangle Formation from Random Stick Breaks

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Solution & Explanation

The problem of determining the probability of forming a triangle from three segments obtained by breaking a stick at two random points can be understood through the lens of the triangle inequality theorem. This theorem states that, for any three segments to form a triangle, the sum of the lengths of any two segments must be greater than the length of the third segment.

Problem Setup

  • Consider a stick of unit length (1).
  • Break the stick at two random points, resulting in three segments.
  • Determine the probability that these segments can form a triangle.

Understanding the Triangle Inequality

For three segments, say of lengths aa, bb, and cc (where a+b+c=1a + b + c = 1), to form a triangle, they must satisfy:

  1. a+b>ca + b > c
  2. b+c>ab + c > a
  3. c+a>bc + a > b

Given the total length is 1, these inequalities can be rewritten as:

  • a+b>0.5a + b > 0.5
  • b+c>0.5b + c > 0.5
  • c+a>0.5c + a > 0.5

The condition implies that no single segment should be greater than 0.5.

Geometric Probability Approach

  1. Random Breaks:

    • Imagine selecting two random points on the stick, xx and yy, such that 0<x<y<10 < x < y < 1.
    • The segments are xx, yxy - x, and 1y1 - y.
  2. Triangle Formation Condition:

    • Each segment must be less than 0.5 to satisfy the triangle inequality.
  3. Visualizing the Solution:

    • Consider a unit square with coordinates (x,y)(x, y) such that 0<x<y<10 < x < y < 1.
    • The condition x<0.5x < 0.5 and yx<0.5y - x < 0.5 and 1y<0.51 - y < 0.5 defines a region within this square.
  4. Calculating the Probability:

    • The feasible region can be visualized as a triangle within the square, bounded by the lines y=x+0.5y = x + 0.5, y=0.5y = 0.5, and x=0.5x = 0.5.
    • The area of this triangle is 14\frac{1}{4} of the total unit square.

Conclusion

The probability that three segments formed by breaking a stick at two random points can form a triangle is 14\frac{1}{4}, or 25%. This result is derived by considering the geometric constraints imposed by the triangle inequality and visualizing the feasible region within a unit square.