End of Year Sale: Use Coupon Code END2025 to Get Extra 25% Off.
longestPath(TreeNode node) that returns an array [inr, dcr].[0, 0].longestPath for the left and right children of the current node.dcr as left_dcr + 1.inr as left_inr + 1.inr and dcr.max(maxval, inr + dcr - 1).[inr, dcr] for the current node.