Leetcode Problem 1425. Constrained Subsequence Sum

1425. Constrained Subsequence Sum

Leetcode Solutions

Approach: Monotonic Deque

  1. Initialize a deque queue and an array dp with the same length as nums.
  2. Iterate i over the indices of nums:
    • If i minus the front of queue is greater than k, remove from the front of queue.
    • Set dp[i] to dp[queue.front()] + nums[i]. If queue is empty, use 0 instead of dp[queue.front()].
    • While dp[queue.back()] is less than dp[i], pop from the back of queue.
    • If dp[i] > 0, push i to the back of queue.
  3. Return the max element in dp.
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Approach: Heap/Priority Queue

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