i and j to 0 to represent the start and end of the sliding window, respectively.cost to 0 to keep track of the current cost of changing the substring.s using the j pointer.
a. Calculate the cost of changing s[j] to t[j] and add it to cost.
b. While cost is greater than maxCost, subtract the cost of changing s[i] to t[i] from cost and increment i to shrink the window.
c. Update the result with the maximum length of the window so far, which is j - i + 1.