left as the minimum value in nums and right as the maximum value in nums.right - left is greater than 10^-5, do the following:
a. Calculate mid as (left + right) / 2.
b. Initialize sum and prev to 0, and min_sum to 0.
c. Iterate through the array, updating sum by adding nums[i] - mid.
d. If i is greater than or equal to k, update min_sum to the minimum of min_sum and prev, and update prev by adding nums[i - k] - mid.
e. If sum is greater than or equal to min_sum, set left to mid. Otherwise, set right to mid.left as the maximum average subarray value.