left to 0 and right to the length of the removable array.left is less than or equal to right:
a. Calculate mid as the average of left and right.
b. Mark the characters at indices removable[0] to removable[mid - 1] in s as removed.
c. Check if p is still a subsequence of the modified s.
d. If p is a subsequence, set left to mid + 1 (try a higher k).
e. If p is not a subsequence, set right to mid - 1 (try a lower k).right as the maximum k.