Leetcode Problem 2873. Maximum Value of an Ordered Triplet I

2873. Maximum Value of an Ordered Triplet I

Leetcode Solutions

Initialize an array rightMax to store the maximum value to the right of each index.
Populate rightMax by iterating from the end of the nums array towards the beginning.
Initialize a variable leftMax to store the maximum value seen so far from the left.
Iterate through the nums array starting from the second element and ending at the second to last element.
For each nums[j], if it is less than leftMax, calculate the triplet value with rightMax[j + 1] and update the maximum value if necessary.
Update leftMax if nums[j - 1] is greater than the current leftMax.
Return the maximum triplet value found, or 0 if no positive triplet value was found.

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