n
is less than or equal to 1, return n
(base case).n
is already computed and stored in the hash map, return the stored result.float('inf')
in Python).n
is divisible by 3, recursively calculate the minimum days for n/3
and update the result.n
is divisible by 2, recursively calculate the minimum days for n/2
and update the result.n-1
and update the result.n
in the hash map.n
.