Leetcode Problem 995. Minimum Number of K Consecutive Bit Flips

995. Minimum Number of K Consecutive Bit Flips

Leetcode Solutions

Greedy Approach with Space Optimization

  1. Initialize a variable flips to keep track of the number of flips made so far.
  2. Iterate through the array from index 0 to n - k (inclusive), where n is the length of the array.
  3. If the current element is a zero (taking into account previous flips), flip the subarray of length k starting from the current index.
  4. To flip, increment the flip count, and add 2 to the current element to mark it as flipped.
  5. As we move beyond the range of k, if we encounter an element greater than 1, decrement flips and restore the element by subtracting 2.
  6. If we encounter a zero in the last k elements of the array, it's impossible to flip it, so return -1.
  7. Return the total number of flips made.
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Sliding Window with Auxiliary Array

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