Leetcode Problem 2366. Minimum Replacements to Sort the Array

2366. Minimum Replacements to Sort the Array

Leetcode Solutions

Greedy Approach for Minimum Replacement to Sort Array

  1. Initialize answer to 0, which will hold the minimum number of operations required.
  2. Start iterating over the array from the second-to-last element to the first element.
  3. For each element nums[i], if it is greater than nums[i + 1], calculate the number of elements nums[i] should be broken into, which is (nums[i] + nums[i + 1] - 1) / nums[i + 1].
  4. Increment answer by the number of elements minus one, as this is the number of operations required.
  5. Update nums[i] to the largest possible value after the operations, which is nums[i] / num_elements.
  6. Continue the iteration until the first element of the array is processed.
  7. Return answer as the result.
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