Leetcode Problem 266. Palindrome Permutation

266. Palindrome Permutation

Leetcode Solutions

Initialize a HashMap to store character frequencies.
Iterate through each character in the string.
For each character, increment its frequency count in the HashMap.
Initialize a variable oddCount to 0 to track the number of characters with odd frequencies.
Iterate through the HashMap entries.
For each entry, if the frequency is odd, increment oddCount.
If oddCount is greater than 1, return false as more than one character has an odd frequency, which is not allowed in a palindrome.
If the loop completes and oddCount is 0 or 1, return true as the string can be permuted to form a palindrome.

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