Leetcode Problem 763. Partition Labels

763. Partition Labels

Leetcode Solutions

Greedy Partitioning with Last Occurrence Map

  1. Create a map to store the last occurrence index for each character in the string.
  2. Initialize anchor to 0 and j to -1, which will represent the start and end of the current partition.
  3. Iterate through the string with index i. a. For each character c at index i, update j to be the maximum of j and the last occurrence index of c. b. If i equals j, we have reached the end of the partition: i. Append the size of the partition (i - anchor + 1) to the result list. ii. Update anchor to i + 1 to start a new partition.
  4. Return the result list containing the sizes of the partitions.
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Two-Pass Hash Table Partitioning

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