dp of size n x n where n is the length of the input array nums.dp array with the values of nums, since when the subarray length is 1, the score difference is the number itself.n, fill in the dp array by considering subarrays nums[i...j].nums[i...j], calculate the score difference for two scenarios: taking the leftmost element (nums[i] - dp[i+1][j]) or the rightmost element (nums[j] - dp[i][j-1]).dp[i][j] with this value.dp array, check if dp[0][n-1] is greater than or equal to 0. If it is, return true, indicating that Player 1 can win; otherwise, return false.