Leetcode Problem 2468. Split Message Based on Limit

2468. Split Message Based on Limit

Leetcode Solutions

Binary Search for Minimum Number of Parts

  1. Check if the limit is too small to fit any suffix; if so, return an empty array.
  2. Initialize the binary search range with low = 0 and high = message.length + 1.
  3. Perform binary search to find the minimum number of parts b: a. Calculate the mid-point mid between low and high. b. Check if mid is a valid number of parts using a helper function isLargerOrFit. c. If mid is valid, update high to mid; otherwise, update low to mid.
  4. After binary search, check if the found number of parts is valid; if not, return an empty array.
  5. Construct the resulting parts using the found number of parts b.
  6. Return the array of parts.
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Brute Force with Direct Calculation

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