Leetcode Problem 2674. Split a Circular Linked List

2674. Split a Circular Linked List

Leetcode Solutions

Slow and Fast Pointer Approach

  1. Initialize two pointers, slow and fast, both pointing to the head of the list.
  2. Traverse the list using the slow and fast pointers until the fast pointer reaches the end of the list or one node before the end.
  3. If the list has an even number of nodes, the fast pointer will end at the last node. If the list has an odd number of nodes, the fast pointer will end one node before the last node.
  4. Adjust the next pointer of the node before the slow pointer to point to the head of the list, creating the end of the first half.
  5. Adjust the next pointer of the last node (where the fast pointer stopped) to point to the node after the slow pointer, creating the head of the second half.
  6. Return the heads of the two halves as an array.
UML Thumbnail

Linear Scan and Split

Ask Question

Programming Language
image/screenshot of info(optional)
Full Screen
Loading...

Suggested Answer

Answer
Full Screen
Copy Answer Code
Loading...