Leetcode Problem 1554. Strings Differ by One Character

1554. Strings Differ by One Character

Leetcode Solutions

String Hashing with Collision Check

  1. Initialize a large prime number MOD to use as the modulus for hashing.
  2. Compute the hash value for each string in the dictionary.
  3. Iterate over each character position in the strings.
  4. For each string, calculate a new hash value with the character at the current position removed.
  5. Use a set to track the new hash values.
  6. If a new hash value is already in the set, return true as we found two strings that differ by one character.
  7. If no such pair is found after checking all positions, return false.
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Brute Force with HashSet

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