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Leetcode Problem 1226. The Dining Philosophers
1226. The Dining Philosophers
AI Mock Interview
Leetcode Solutions
Semaphore with Mutex Locks
Solution Idea
Algorithm Steps
Code Implementation
Initialize a semaphore with a count of 4 to allow a maximum of four philosophers to pick up forks simultaneously.
When a philosopher wants to eat, they first call
wait()
on the semaphore to decrease the count.
If the semaphore count is greater than zero, the philosopher proceeds to pick up the forks; otherwise, they wait.
The philosopher picks up the left fork and then the right fork, each time using a mutex lock to ensure exclusive access to the fork.
After picking up both forks, the philosopher calls the
eat()
function.
The philosopher puts down the right fork and then the left fork, again using mutex locks to ensure exclusive access.
The philosopher calls
signal()
on the semaphore to increase the count, allowing another philosopher to proceed.
Repeat steps 2-7 as necessary.
Odd-Even Philosopher Approach
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