Leetcode Problem 1532. The Most Recent Three Orders

1532. The Most Recent Three Orders

Leetcode Solutions

Using Window Functions for Recent Orders

Use the RANK() window function to assign a rank to each order for each customer based on the order date in descending order.
Perform an inner join between the Customers and Orders tables on the customer_id field.
Filter the results to only include orders where the rank is less than or equal to 3, which gives us the three most recent orders for each customer.
Order the final result by customer name in ascending order, customer_id in ascending order, and order date in descending order.
Select the required columns: customer name, customer_id, order_id, and order date.


erDiagram
    CUSTOMERS {
        int customer_id PK "Unique customer identifier"
        varchar name "Customer's name"
    }
    ORDERS {
        int order_id PK "Unique order identifier"
        date order_date "Date when the order was placed"
        int customer_id FK "Identifier for the customer who made the order"
        int cost "Cost of the order"
    }
    CUSTOMERS ||--o{ ORDERS : places

Using JOIN and GROUP BY with HAVING Clause

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Leetcode Problem 1532. The Most Recent Three Orders

Leetcode Solutions

Using Window Functions for Recent Orders

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Query Steps

Code Implementation

Using JOIN and GROUP BY with HAVING Clause

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