left
at 0 and right
at len(s) - 1
.operations
to 0.left < right
:
a. If s[left]
is not equal to s[right]
, increment operations
.
b. If operations
is greater than 2, return false
.
c. Move left
pointer to the right and right
pointer to the left.true
if the loop completes, indicating the string can be made a palindrome with at most two operations.