Leetcode Problem 1518. Water Bottles

1518. Water Bottles

Leetcode Solutions

Iterative Exchange Approach

  1. Initialize totalDrunk to numBottles (the initial number of full bottles).
  2. Initialize emptyBottles to numBottles (since all bottles will be empty after drinking).
  3. While emptyBottles is greater than or equal to numExchange: a. Calculate newBottles as the quotient of emptyBottles divided by numExchange. b. Add newBottles to totalDrunk. c. Update emptyBottles to newBottles (new full bottles) plus the remainder of emptyBottles divided by numExchange (leftover empty bottles).
  4. Return totalDrunk as the maximum number of bottles that can be drunk.
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Accumulative Sum Approach

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