sum to 0 to keep track of the total number of arithmetic subarrays.count to 0 to keep track of the current run of consecutive elements forming an arithmetic subarray.nums[i] - nums[i-1] is the same as nums[i-1] - nums[i-2]).count.count * (count + 1) / 2 to sum, and reset count to 0.count * (count + 1) / 2 to sum to account for the last run.sum.