Leetcode Problem 1006. Clumsy Factorial

1006. Clumsy Factorial

Leetcode Solutions

Observation Based Approach

Check if n is less than or equal to 2, return n as the result.
Check if n is less than or equal to 4, return n + 3 as the result.
For n greater than 4, calculate the number of chunks by dividing n by 4.
Determine the number of elements left after forming chunks.
If there are 0 elements left, the result is n + 1.
If there is 1 or 2 elements left, the result is n + 2.
If there are 3 elements left, the result is n - 1.
Return the calculated result.

Using Stack to Simulate Operations

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