Leetcode Problem 2753. Count Houses in a Circular Street II

2753. Count Houses in a Circular Street II

Leetcode Solutions

Initialize x to 0 to keep track of the number of moveRight() operations.
Initialize find_first to False to indicate that the first open door has not been found yet.
Loop for at most 2 * k steps to ensure we don't exceed the maximum bound for the number of houses. a. At each step, use isDoorOpen() to check the state of the current door. b. If the door is open and find_first is False, set find_first to True and record the index as x_first. c. If the door is open and find_first is True, calculate the distance from the first open door as dist_from_first = x - x_first and close the door using closeDoor(). d. Increment x and move to the next house on the right using moveRight().
Once the loop is complete, return dist_from_first as the total number of houses.

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