1 is present in the array. If not, return 1 as the answer.n by 1s.a in the array, negate the value at index abs(a) - 1 if it is positive, to mark a as present. Use index 0 to record the presence of n.1. The first index with a positive value indicates the smallest missing positive integer.1 to n - 1 are negative, check the value at index 0. If it's positive, return n, otherwise return n + 1.