0
Leetcode Problem 289. Game of Life
289. Game of Life
AI Mock Interview
Leetcode Solutions
In-Place Solution with State Encoding
Solution Idea
Algorithm Steps
Code Implementation
Complexity Analysis
Iterate through each cell in the board.
Count the live neighbors for each cell.
Apply the rules of the game to determine the next state:
If a live cell has fewer than two or more than three live neighbors, set its value to 2 (live to dead).
If a dead cell has exactly three live neighbors, set its value to 3 (dead to live).
Otherwise, keep the current state.
Iterate through the board again and update the cells to their new state:
If a cell's value is 2, set it to 0 (dead).
If a cell's value is 3, set it to 1 (live).
Otherwise, keep the current state.
Extra Memory Solution with Copy of the Board
Ask Question
Programming Language
Purpose:
General Question
Debug My Code
image/screenshot of info
(optional)
[+]
Full Screen
Loading...
Get Answer
Suggested Answer
Answer
Full Screen
Copy Answer Code
Loading...