findKthSymbol that takes the current row number n, the position k, and the value of the root node rootVal as arguments.n is 1, return rootVal as the base case.totalNodes = 2^(n - 1).k is in the left or right half of the row. If k <= totalNodes / 2, the target is in the left subtree; otherwise, it's in the right subtree.findKthSymbol(n - 1, k, rootVal) recursively.k to k - totalNodes / 2 and call findKthSymbol(n - 1, k, 1 - rootVal) recursively.findKthSymbol(n, k, 0).