lo to 1 and hi to m * n as the range of possible values for the kth smallest number.lo is less than hi:
a. Calculate mid as the average of lo and hi.
b. Define enough(x) to count the number of values less than or equal to mid in the table.
c. For each row i from 1 to m, add min(mid // i, n) to the count.
d. If the count is at least k, set hi to mid.
e. Otherwise, set lo to mid + 1.hi as the kth smallest number.