Leetcode Problem 925. Long Pressed Name

925. Long Pressed Name

Leetcode Solutions

Initialize two pointers i and j to 0 for name and typed respectively.
Loop while j is less than the length of typed: a. If i is less than the length of name and name[i] equals typed[j], increment both i and j. b. Else if j is greater than 0 and typed[j] equals typed[j-1], increment j only. c. Else, return false.
After the loop, if i equals the length of name, return true. Otherwise, return false.

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