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n to the length of s.memo with dimensions n x n, initialized with zeros.lps that takes parameters i, j, and memo.
memo[i][j] is not zero, return its value (memoization).i > j, return 0 (base case: empty substring).i == j, return 1 (base case: single character substring).s[i] == s[j], set memo[i][j] to 2 + lps(i + 1, j - 1, memo).memo[i][j] to max(lps(i, j - 1, memo), lps(i + 1, j, memo)).lps(0, n - 1, memo).