Leetcode Problem 2673. Make Costs of Paths Equal in a Binary Tree
2673. Make Costs of Paths Equal in a Binary Tree
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Leetcode Solutions
Bottom-Up Approach with Cost Balancing
Solution Idea
Algorithm Steps
Code Implementation
Complexity Analysis
Initialize a variable
totalIncrements
to store the total number of increments needed.
Iterate over the nodes from the last node up to the second node in pairs of two (sibling nodes).
For each pair of sibling nodes, calculate the difference in their costs.
Increment
totalIncrements
by the absolute value of the difference.
Update the cost of the parent node to be the sum of its current cost and the maximum cost of its two children.
Continue this process until all sibling pairs have been processed.
Return
totalIncrements
as the result.
Recursive DFS to Balance Costs
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