Leetcode Problem 570. Managers with at Least 5 Direct Reports

570. Managers with at Least 5 Direct Reports

Leetcode Solutions

Finding Managers with at Least Five Direct Reports

Use a GROUP BY clause on the managerId column of the Employee table to aggregate the data by managers.
Apply the COUNT() function to count the number of direct reports for each manager.
Use the HAVING clause to filter the results to only include managers with five or more direct reports.
Join the filtered result with the original Employee table to get the names of the managers.
Select the name column from the Employee table where the id matches the managerId from the filtered result.

erDiagram
    Employee {
        int id PK "The unique identifier for an employee"
        varchar name "The name of the employee"
        varchar department "The department where the employee works"
        int managerId "The identifier for the employee's manager"
    }
    Employee ||--o{ Employee : manages

Using Subquery with IN Clause to Identify Managers with Five or More Direct Reports

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Leetcode Problem 570. Managers with at Least 5 Direct Reports

Leetcode Solutions

Finding Managers with at Least Five Direct Reports

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Using Subquery with IN Clause to Identify Managers with Five or More Direct Reports

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