Leetcode Problem 221. Maximal Square

221. Maximal Square

Leetcode Solutions

Initialize maxSquareLength to 0 to keep track of the maximum length of a square found so far.
Create a 2D DP array dp with the same dimensions as the input matrix, initialized to 0.
Iterate over each cell (i, j) in the input matrix. a. If matrix[i][j] is 1, update dp[i][j] to min(dp[i-1][j], dp[i][j-1], dp[i-1][j-1]) + 1. b. Update maxSquareLength to the maximum of its current value and dp[i][j].
After completing the iteration, return the area of the largest square, which is maxSquareLength * maxSquareLength.

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