Leetcode Problem 2932. Maximum Strong Pair XOR I

2932. Maximum Strong Pair XOR I

Leetcode Solutions

Brute-Force Approach

  1. Initialize a variable maxXor to 0 to keep track of the maximum XOR value.
  2. Iterate through the array nums using two nested loops to consider all possible pairs (including a number with itself).
  3. For each pair (x, y), check if |x - y| <= min(x, y) to determine if it's a strong pair.
  4. If it is a strong pair, calculate the XOR of x and y and update maxXor if this XOR is greater than the current maxXor.
  5. After considering all pairs, return maxXor as the result.
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Sorting and Pairwise XOR

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