Leetcode Problem 1829. Maximum XOR for Each Query

1829. Maximum XOR for Each Query

Leetcode Solutions

Prefix XOR and Bitwise Complement

  1. Initialize k to (1 << maximumBit) - 1 which is the maximum value k can take.
  2. Calculate the cumulative XOR (prefix XOR) for the entire array.
  3. Initialize an empty list result to store the answers for each query.
  4. Iterate over the array in reverse, and for each element: a. Calculate the answer for the current query by XORing the current prefix XOR with k. b. Append the answer to the result list. c. Update the prefix XOR by XORing it with the current element (effectively removing the last element from the cumulative XOR).
  5. Reverse the result list to get the answers in the correct order.
  6. Return the result list.
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Brute Force with Bit Manipulation

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