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left to the smallest element in the matrix and right to the largest element.(m * n) / 2 since the matrix has an odd number of elements.mid as the average of left and right.
b. Count the number of elements in the matrix less than or equal to mid using a helper function that performs binary search on each row.
c. If the count is less than or equal to the median position, set left to mid + 1; otherwise, set right to mid.left meets right, the median value is found, and we return left.