Leetcode Problem 1681. Minimum Incompatibility

1681. Minimum Incompatibility

Leetcode Solutions

Dynamic Programming with Bitmasking

  1. Define dp[mask] to store the minimum incompatibility for the subset represented by mask.
  2. Initialize dp[0] to 0 and all other dp[mask] to infinity.
  3. Sort the nums array to ensure subsets are formed with increasing values.
  4. Iterate over all possible bitmasks mask.
  5. For each mask, iterate over all possible subsets submask that can be formed from mask.
  6. If submask represents a valid subset (no duplicates and correct size), calculate its incompatibility.
  7. Update dp[mask] with the minimum value between the current dp[mask] and dp[mask ^ submask] + incompatibility.
  8. After all iterations, return dp[(1 << n) - 1] if it's not infinity, otherwise return -1.
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Backtracking with Pruning

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