dp of size (n + 1) x (k + 1) with all elements set to 0, where n is the length of the string s. Set dp[n][0] to 1, as there is one way to partition an empty string with 0 partitions left.primesum of size (k + 1) x (n + 1) with all elements set to 0. This array will store prefix sums of the dp array.s in reverse, starting from the last index and moving towards the first.i, check if the character at s[i] is a prime digit.dp[i][l] for all l from 1 to k by adding the value of primesum[l - 1][-minLength] to it.primesum array by adding the current dp[i][l] value to the last element of primesum[l] if s[i] is a prime digit and i is the first index or the previous character is not a prime digit.dp[0][k] modulo 10^9 + 7 as the final answer.