dp with the same dimensions as grid and fill it with -1 to represent unvisited cells.dfs(i, j) that computes the number of increasing paths ending at grid[i][j].
dp[i][j] is not -1, return dp[i][j] as the result is already computed.dp[i][j] to 1 (the cell itself is a path).dp[i][j] by the result of dfs on the neighbor cell.dp[i][j].grid and call dfs(i, j) for each cell.dp to get the total number of strictly increasing paths.10^9 + 7.