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Leetcode Problem 265. Paint House II

265. Paint House II

Leetcode Solutions

Dynamic programming with Optimized Time and Space

  1. Initialize two variables to store the indices of the first and second minimum costs from the previous row.
  2. Initialize two variables to store the values of the first and second minimum costs from the previous row.
  3. Iterate through each house (row in the costs matrix).
  4. For the current house, initialize temporary variables to store the indices and values of the new minimum and second minimum costs.
  5. Iterate through each color for the current house.
  6. If the color index matches the index of the previous minimum cost, add the second minimum cost to the current painting cost. Otherwise, add the minimum cost.
  7. Update the temporary variables for the new minimum and second minimum costs accordingly.
  8. After processing all colors for the current house, update the variables for the minimum and second minimum costs with the values from the temporary variables.
  9. After processing all houses, return the minimum cost, which is the first minimum cost after processing the last house.
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Dynamic Programming with O(nk) Space

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