Leetcode Problem 132. Palindrome Partitioning II

132. Palindrome Partitioning II

Leetcode Solutions

Dynamic Programming - Bottom Up (Tabulation)

  1. Initialize a table cutsDp with cutsDp[i] representing the minimum cuts needed for the substring s[0...i].\n2. Set cutsDp[i] to i for all i, since the maximum cuts needed is i (cutting between each character).\n3. Iterate over the string with index mid from 0 to n-1, considering both odd and even length palindromes.\n4. For each mid, expand around the center to find the longest palindrome and update cutsDp using the formula cutsDp[end] = min(cutsDp[end], 1 + cutsDp[start - 1]).\n5. After the loop, return cutsDp[n - 1] as the minimum number of cuts needed for the entire string.
UML Thumbnail

Backtracking

Ask Question

Programming Language
image/screenshot of info(optional)
Full Screen
Loading...

Suggested Answer

Answer
Full Screen
Copy Answer Code
Loading...