🚀

End of Year Sale: Use Coupon Code END2025 to Get Extra 25% Off.

04DAYS
:
01HOURS
:
54MINUTES
:
26SECONDS

Leetcode Problem 1106. Parsing A Boolean Expression

1106. Parsing A Boolean Expression

Leetcode Solutions

Iterative Stack-Based Parsing

  1. Initialize an empty stack.
  2. Iterate over each character in the expression.
  3. If the character is not a comma , or closing parenthesis ), push it onto the stack.
  4. If the character is a closing parenthesis ), pop characters from the stack until an opening parenthesis ( is encountered, collecting the characters in a temporary list or set.
  5. Pop the operator from the stack (it will be one of &, |, !).
  6. Evaluate the sub-expression based on the operator and the collected characters.
  7. Push the result of the sub-expression ('t' or 'f') onto the stack.
  8. After the iteration is complete, the stack should contain a single character, which is the result of the entire expression.
  9. Return True if the character is 't', otherwise return False.
UML Thumbnail

Recursive Descent Parsing

Ask Question

Programming Language
image/screenshot of info(optional)
Full Screen
Loading...

Suggested Answer

Answer
Full Screen
Copy Answer Code
Loading...