Leetcode Problem 1106. Parsing A Boolean Expression

1106. Parsing A Boolean Expression

Leetcode Solutions

Initialize an empty stack.
Iterate over each character in the expression.
If the character is not a comma , or closing parenthesis ), push it onto the stack.
If the character is a closing parenthesis ), pop characters from the stack until an opening parenthesis ( is encountered, collecting the characters in a temporary list or set.
Pop the operator from the stack (it will be one of &, |, !).
Evaluate the sub-expression based on the operator and the collected characters.
Push the result of the sub-expression ('t' or 'f') onto the stack.
After the iteration is complete, the stack should contain a single character, which is the result of the entire expression.
Return True if the character is 't', otherwise return False.

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