prev to 0 to keep track of the previous number in the array.prev.
b. Perform a binary search on the list of primes to find the largest prime less than or equal to this maximum value.
c. Subtract the found prime from the current number.
d. If no such prime can be found, check if the current number is already greater than prev. If not, return false.
e. Update prev to the new value of the current number.