Leetcode Problem 1076. Project Employees II

1076. Project Employees II

Leetcode Solutions

Using GROUP BY and HAVING with a Subquery

Use GROUP BY to aggregate the data by project_id.\n- Use COUNT(employee_id) to get the number of employees per project.\n- Use a subquery to find the maximum count of employees across all projects.\n- Use the HAVING clause to filter the projects that have a count of employees equal to the maximum count found in the subquery.

\nerDiagram\n    Employee ||--o{ Project : works_on\n    Employee {\n        int employee_id PK\n        varchar name\n        int experience_years\n    }\n    Project {\n        int project_id PK\n        int employee_id PK\n    }\n

Using Window Function RANK() Over a Counted Subquery

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