Leetcode Problem 203. Remove Linked List Elements

203. Remove Linked List Elements

Leetcode Solutions

Sentinel Node Approach

  1. Create a sentinel node and set its next pointer to the head of the list.
  2. Initialize two pointers, prev as the sentinel node and curr as the head of the list.
  3. Iterate through the list while curr is not null.
  4. If curr.val equals val, set prev.next to curr.next to remove curr from the list.
  5. If curr.val does not equal val, set prev to curr to move the prev pointer forward.
  6. Move curr to the next node in the list.
  7. After the iteration, return sentinel.next, which is the new head of the modified list.
UML Thumbnail

Iterative Approach without Sentinel Node

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